wujxh2011 - 2013/6/11 9:21:00
25‘C时,测得比重瓶充满水时的质量为55.0622g,瓶加沥青再充满水时的质量为55.1892g,其中沥青质量为15g,求沥青的相对密度和密度?(保留三位小数,25‘C时水的相对体积为0.99098)请写出详细步骤谢谢!!=W#wÞ[Æ%bbs.3c3t.comL2|×&I¨¾
pl13142 - 2013/6/11 14:48:00
相对密度=沥青质量/(沥青+瓶装满水质量)-比重瓶装沥青水的质量=W#wÞ[Æ%bbs.3c3t.comL2|×&I¨¾
密度=相对密度x水密度(25或15摄氏度时的密度)=W#wÞ[Æ%bbs.3c3t.comL2|×&I¨¾
johnsonzzs - 2013/6/15 17:02:00
沥青的体积计算: =W#wÞ[Æ%bbs.3c3t.comL2|×&I¨¾
1、除去沥青外瓶和水的质量:55.1892g-15g=40.1892g =W#wÞ[Æ%bbs.3c3t.comL2|×&I¨¾
2、和沥青等体积的水的质量:55.0622g-40.1892g =14.8730g=W#wÞ[Æ%bbs.3c3t.comL2|×&I¨¾
3、沥青的体积:14.873g/0.99098g/cm^3=15.0084cm^3=W#wÞ[Æ%bbs.3c3t.comL2|×&I¨¾
4、25度时沥青的密度:15/15.0084=0.999g/cm^3=W#wÞ[Æ%bbs.3c3t.comL2|×&I¨¾
5、25度时沥青的相对密度:15/14.873=1.009=W#wÞ[Æ%bbs.3c3t.comL2|×&I¨¾
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应该是这样算的~~ 抛砖引玉哈=W#wÞ[Æ%bbs.3c3t.comL2|×&I¨¾