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skyness - 2012/6/13 15:08:00
1、一根简支搁置的钢筋混凝土梁宽50cm,高100cm,跨距6m,单位长度重量12.4KN/m,试判别下列各题:①自重情况下,梁的路中弯矩两支座处剪力分别为;ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
②在梁的跨中施加50KN集中荷载,则梁跨中弯矩和支座剪力分别为;ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
③在梁的二个三分点处(即距2个支座各2米处)各施加30KN荷载,则梁跨中弯矩和支座剪力分别为。ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
2、某工程对一根长40m的预应力混凝土空心桩进行静载桩试验,要求进行到地基土破坏,桩身截面尺寸为500mm×500mm。空心直径200mm,桩顶和桩端各有2m空心段,预计沉桩最大试验荷载36000KN。ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
①试桩与锚桩之间中心距不得小于()ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
②试验采用快速维持荷载法,每级加载和卸载时间分别为()ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
③各级荷载及桩顶对应沉降见下表ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
荷载KNƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
600ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
900ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
1200ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
1500ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
1800ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
2100ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
2400ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
2700ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
300ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
3300ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
3600ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
沉降mmƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
2.1ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
3.8ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
5.7ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
8.0ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
10.5ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
13.2ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
16.3ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
19.6ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
23.4ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
44.5ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
76.8ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
沉桩极限承载力()ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
④试验时采用10根对称布置的锚桩,锚桩尺寸与试桩相同,锚桩主筋采用Φ25钢筋,抗拉强度设计值为310KPa,则每根锚桩至少配置()根Φ25钢筋,写出计算过程。ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
⑥桩的极限端阻力(),写出计算过程。ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
5、某梁跨中载面处测点布置如下图所示,已知ε1=-90με,ε2=-80με,ε3=10με,ε4=100με,ε5=110με,E=30GPa,截面宽b=100mm,截面高h=200mm,求该截面上的轴力N和弯矩Myƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
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ym00022112 - 2012/6/13 15:31:00
计算题太多了呢ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
tx751206 - 2012/7/15 9:42:00
有的难度!!!1ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
zhyby - 2012/12/30 10:30:00
真的难啊,刚出学校门的容易考,结构力学都是类似计算ƒ‡Ï nkRFbbs.3c3t.com©öJÞ@½¡Ã×
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