メ逍遥浪子メ - 2008/9/10 10:42:00
在隧道喷射混凝土抗压强度试验中,一般采用大板切割法取100*100*100的三块为一组试件,在计算它的抗压强度时要乘以0.95的系数转换,究竟是在什么时候才乘以0.95呢?例如:C20的喷砼,一组力值为:255KN 258KN 249KNp)qEW5ñêsbbs.3c3t.com£bB48
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1.p)qEW5ñêsbbs.3c3t.com£bB48
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255/10*0.95=24.2p)qEW5ñêsbbs.3c3t.com£bB48
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258/10*0.95=24.5p)qEW5ñêsbbs.3c3t.com£bB48
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249/10*0.95=23.7p)qEW5ñêsbbs.3c3t.com£bB48
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取平均值(24.2+24.5+23.7)/3=24.1MPap)qEW5ñêsbbs.3c3t.com£bB48
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2.p)qEW5ñêsbbs.3c3t.com£bB48
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255/10=25.5p)qEW5ñêsbbs.3c3t.com£bB48
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258/10=25.8p)qEW5ñêsbbs.3c3t.com£bB48
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249/10=24.9p)qEW5ñêsbbs.3c3t.com£bB48
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取平均值(25.5+25.8+24.9)/3=25.4p)qEW5ñêsbbs.3c3t.com£bB48
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25.4*0.95=24.1MPap)qEW5ñêsbbs.3c3t.com£bB48
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p)qEW5ñêsbbs.3c3t.com£bB48
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那个处理结果正确呢?依据是那本规范上的说明?p)qEW5ñêsbbs.3c3t.com£bB48
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ningjipan - 2008/9/10 13:00:00
按照第二个方法处理p)qEW5ñêsbbs.3c3t.com£bB48
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137285966 - 2008/9/10 20:44:00
按照第一中的方法,算的平均值只是这组试件的代表值,而0.95的系数是对每个强度值而言,p)qEW5ñêsbbs.3c3t.com£bB48
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