メ逍遥浪子メ - 2008/9/10 10:42:00
在隧道喷射混凝土抗压强度试验中,一般采用大板切割法取100*100*100的三块为一组试件,在计算它的抗压强度时要乘以0.95的系数转换,究竟是在什么时候才乘以0.95呢?例如:C20的喷砼,一组力值为:255KN 258KN 249KNón¯:Íæ+bbs.3c3t.comÃL¾økfɹ
1.ón¯:Íæ+bbs.3c3t.comÃL¾økfɹ
255/10*0.95=24.2ón¯:Íæ+bbs.3c3t.comÃL¾økfɹ
258/10*0.95=24.5ón¯:Íæ+bbs.3c3t.comÃL¾økfɹ
249/10*0.95=23.7ón¯:Íæ+bbs.3c3t.comÃL¾økfɹ
取平均值(24.2+24.5+23.7)/3=24.1MPaón¯:Íæ+bbs.3c3t.comÃL¾økfɹ
2.ón¯:Íæ+bbs.3c3t.comÃL¾økfɹ
255/10=25.5ón¯:Íæ+bbs.3c3t.comÃL¾økfɹ
258/10=25.8ón¯:Íæ+bbs.3c3t.comÃL¾økfɹ
249/10=24.9ón¯:Íæ+bbs.3c3t.comÃL¾økfɹ
取平均值(25.5+25.8+24.9)/3=25.4ón¯:Íæ+bbs.3c3t.comÃL¾økfɹ
25.4*0.95=24.1MPaón¯:Íæ+bbs.3c3t.comÃL¾økfɹ
ón¯:Íæ+bbs.3c3t.comÃL¾økfɹ
那个处理结果正确呢?依据是那本规范上的说明?ón¯:Íæ+bbs.3c3t.comÃL¾økfɹ
ningjipan - 2008/9/10 13:00:00
按照第二个方法处理ón¯:Íæ+bbs.3c3t.comÃL¾økfɹ
137285966 - 2008/9/10 20:44:00
按照第一中的方法,算的平均值只是这组试件的代表值,而0.95的系数是对每个强度值而言,ón¯:Íæ+bbs.3c3t.comÃL¾økfɹ