进来在学习JTG E51-2009,看到关于无侧限抗压强度计算，当变异系数Cv超过规定值时，则需按允许误差10%和90%的概率重新计算所需的试件数量，公式如下]`zXã bbs.3c3t.comfåm9F}cvë
]`zXã bbs.3c3t.comfåm9F}cvë
n=t1-a/2 Cv│e│]`zXã bbs.3c3t.comfåm9F}cvë
]`zXã bbs.3c3t.comfåm9F}cvë
]`zXã bbs.3c3t.comfåm9F}cvë
]`zXã bbs.3c3t.comfåm9F}cvë
]`zXã bbs.3c3t.comfåm9F}cvë
假如我做的是小试件，规定Cv≤6%，可我最后算下来是7.5%，请问那我应该怎么计算试件数量n？]`zXã bbs.3c3t.comfåm9F}cvë
谢谢！]`zXã bbs.3c3t.comfåm9F}cvë
%20(2)_1.gif)
