进来在学习JTG E51-2009,看到关于无侧限抗压强度计算,当变异系数Cv超过规定值时,则需按允许误差10%和90%的概率重新计算所需的试件数量,公式如下u>ÊîzpÌabbs.3c3t.com%2hHx+È:
u>ÊîzpÌabbs.3c3t.com%2hHx+È:
n=t1-a/2 Cv│e│u>ÊîzpÌabbs.3c3t.com%2hHx+È:
u>ÊîzpÌabbs.3c3t.com%2hHx+È:
u>ÊîzpÌabbs.3c3t.com%2hHx+È:
u>ÊîzpÌabbs.3c3t.com%2hHx+È:
u>ÊîzpÌabbs.3c3t.com%2hHx+È:
假如我做的是小试件,规定Cv≤6%,可我最后算下来是7.5%,请问那我应该怎么计算试件数量n?u>ÊîzpÌabbs.3c3t.com%2hHx+È:
谢谢!u>ÊîzpÌabbs.3c3t.com%2hHx+È: