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[交流] 关于公路基层强度评定的问题(哪种方法正确) [复制链接]

1#
如题:某高速公路水泥稳定碎石基层,已知设计抗压强度Rd=3.1MPa,现测得某段的无侧限抗压强度数值如下,对该段强度结果进行评定并计算其得分值。(规定分为20分,保证率为95%,Za=1.645)3.85'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
4.01'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
3.53'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
3.96'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
4.00'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
3.73'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
3.86'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
3.97'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
3.93'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
4.05'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
3.52'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
3.83
'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
第一种解答:'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
R=3.85'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
Cv=0.046
'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
Rd/(1-ZaCv)=3.1/(1-1.645*0.046)=3.35'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
R>Rd/(1-ZaCv)
'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
合格,得满分20分。
'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
我看了也有资料上这样解答: '­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
答案:'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
1)计算平均值'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
,标准偏差S、变异系数
Cv:R=3.85'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
Cv=0.046    S=0.178
'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
2)计算代表值:'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
保证率为95%的保证率系数Za=1.645'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
∴代表值=3.85-0.178*1.645=3.56
'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
3)评定:'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
3.563.2'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
∴该段的无侧限抗压强度合格
'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
4)计算得分值:'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
得分值=20分(规定的满分)
'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
个人认为第二种解答求出的是该组数据的代表值,不适用于路段的强度评定,不知大家有何不同见解,欢迎讨论!'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
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2#

同意!'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
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3#

我认为第二种符合现行的规范。第一种是质量检验评定标准上,第二种才是无机物结合料2009版的评定方法'­¤A¤Ë?^e:bbs.3c3t.com¿7Ö× ÷p­/î
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