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钢筋抗拉强度、屈服强度结果修约规定是怎样的?结果保留0、5、10... [复制链接]

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回复:钢筋抗拉强度、屈服强度结果修约规定是怎样的?结果保留0、5、10整数倍又是什么意思呢?

数据修约规则(GB8170-87)中ßuÿ=ôi!ö–ñbbs.3c3t.com{.Nl©†z–=
   5.1   0.5单位修约ßuÿ=ôi!ö–ñbbs.3c3t.com{.Nl©†z–=
将拟修约数值乘以2,按指定数位依第3章规则修约,所得数值再除以2。ßuÿ=ôi!ö–ñbbs.3c3t.com{.Nl©†z–=
          拟修约数值                      乘2                      2A修约值                            A修约值        ßuÿ=ôi!ö–ñbbs.3c3t.com{.Nl©†z–=
                 A                               2A                  ( 修约间隔为10)                ( 修约间隔为5)ßuÿ=ôi!ö–ñbbs.3c3t.com{.Nl©†z–=
              378.3                         756.6                         760                                     380ßuÿ=ôi!ö–ñbbs.3c3t.com{.Nl©†z–=
              530.7                         1061.4                       1060                                   530ßuÿ=ôi!ö–ñbbs.3c3t.com{.Nl©†z–=
              372.5                         745                            740                                     370ßuÿ=ôi!ö–ñbbs.3c3t.com{.Nl©†z–=
最后编辑niuniu6682000 最后编辑于 2008-07-31 20:56:38
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