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  • 2010-01-04
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发表于 2010-06-21 14:36 |显示全部
                                                                                            ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
2下列表格中的数据为做CBR试验十所测得的结果，请将所需数据填在表格空白处，并计算CBR2.5和CBR5，P判断该试验是否重做。ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
(已知：量力环校正系数C=200N/0.01mm,贯入杆直径d=50mmӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
荷载测力计百分表读数Rӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
单位压力P(KPa)ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
百分表读数(0.01mmӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
贯入量Lmmӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
0.9ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
(92)ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
60.5ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
(0.61)ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
1.8ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
(183)ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
106.5ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
(1.07)ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
2.9ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
（ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
151ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
4.0ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
194ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
4.8ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
240.5ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
5.1ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
286ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
解：根据贯入杆的单位压力计算公式ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
P=C*R/Aӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
则P=200X0.9/1963=0.092 ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
MPaӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
0.092X1000=9（KPa）ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
P=200X1.8/1963=0.183 MPaӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
0.183X1000=183 (MPa)ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
(其中 A=1/4Πd2ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
=1/4X3.14X502 =1963ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
请问，贯入量是如何计算的？ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
1 某工地地基原状土直剪试验（快剪）结果如下表，试求该地基的强度指标ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
σ (KPa)ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
100ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
200ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
300ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
τ( KPa)ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
100ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
108ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
115ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
解:ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
（1）直剪试验在直角坐标σ~τ关系图是线性的，表达式是τ =σtgΦ+Cӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
(2)作图如下：ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
（3）tgΦ=15%200=0.075ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
Φ=4.3oӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
C=100-100tgΦӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
C=92.5(KPa)ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
请问我这样做是正确的吗？那么ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
（3）中的tgΦ=15%200中的15和200是怎样确定的？ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
C=100-100tgΦ中的两个100是怎样确定的？ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
ӟ¶>Zô»bbs.3c3t.comC `è‹Åmm4
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