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yzyzz
- 游客
- 1700
- 1904
- 2010-01-04
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发表于 2010-06-21 14:36
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ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ2下列表格中的数据为做CBR试验十所测得的结果，请将所需数据填在表格空白处，并计算CBR2.5和CBR5，P判断该试验是否重做。ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ(已知：量力环校正系数C=200N/0.01mm,贯入杆直径d=50mmä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ荷载测力计百分表读数Rä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
单位压力P(KPa)ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
百分表读数(0.01mmä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
贯入量Lmmä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ0.9ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
(92)ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
60.5ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
(0.61)ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ1.8ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
(183)ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
106.5ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
(1.07)ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ2.9ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
（ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
151ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ4.0ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
194ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ4.8ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
240.5ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ5.1ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
286ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ解：根据贯入杆的单位压力计算公式ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
P=C*R/Aä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ则P=200X0.9/1963=0.092 ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
MPaä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
0.092X1000=9（KPa）ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
P=200X1.8/1963=0.183 MPaä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
0.183X1000=183 (MPa)ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
(其中 A=1/4Πd2ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
=1/4X3.14X502 =1963ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ请问，贯入量是如何计算的？ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ1 某工地地基原状土直剪试验（快剪）结果如下表，试求该地基的强度指标ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
σ (KPa)ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
| 100ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
| 200ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
| 300ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
| τ( KPa)ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
| 100ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
| 108ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
| 115ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
|
ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
解:ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
（1）直剪试验在直角坐标σ~τ关系图是线性的，表达式是τ =σtgΦ+Cä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
(2)作图如下：ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
（3）tgΦ=15%200=0.075ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
Φ=4.3oä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
C=100-100tgΦä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
C=92.5(KPa)ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
请问我这样做是正确的吗？那么ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
（3）中的tgΦ=15%200中的15和200是怎样确定的？ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
C=100-100tgΦ中的两个100是怎样确定的？ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
ä1|º±µ±Übbs.3c3t.comäÌ],ÙïÎnæ
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