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  • 2010-01-04
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发表于 2010-06-21 14:36 |只看楼主
                                                                                            tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
2下列表格中的数据为做CBR试验十所测得的结果，请将所需数据填在表格空白处，并计算CBR2.5和CBR5，P判断该试验是否重做。tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
(已知：量力环校正系数C=200N/0.01mm,贯入杆直径d=50mmtOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
荷载测力计百分表读数RtOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
单位压力P(KPa)tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
百分表读数(0.01mmtOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
贯入量LmmtOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
0.9tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
(92)tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
60.5tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
(0.61)tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
1.8tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
(183)tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
106.5tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
(1.07)tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
2.9tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
（tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
151tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
4.0tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
194tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
4.8tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
240.5tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
5.1tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
286tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
解：根据贯入杆的单位压力计算公式tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
P=C*R/AtOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
则P=200X0.9/1963=0.092 tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
MPatOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
0.092X1000=9（KPa）tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
P=200X1.8/1963=0.183 MPatOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
0.183X1000=183 (MPa)tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
(其中 A=1/4Πd2tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
=1/4X3.14X502 =1963tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
请问，贯入量是如何计算的？tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
1 某工地地基原状土直剪试验（快剪）结果如下表，试求该地基的强度指标tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
σ (KPa)tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
100tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
200tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
300tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
τ( KPa)tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
100tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
108tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
115tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
解:tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
（1）直剪试验在直角坐标σ~τ关系图是线性的，表达式是τ =σtgΦ+CtOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
(2)作图如下：tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
（3）tgΦ=15%200=0.075tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
Φ=4.3otOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
C=100-100tgΦtOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
C=92.5(KPa)tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
请问我这样做是正确的吗？那么tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
（3）中的tgΦ=15%200中的15和200是怎样确定的？tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
C=100-100tgΦ中的两个100是怎样确定的？tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
tOdqÏÉp" nbbs.3c3t.comŒ BÅ2g(ñ¾î
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