钢筋抗拉强度、屈服强度结果修约规定是怎样的？结果保留0、5、10... [复制链接]

我们是认为这样取舍按照0   5  10是5的倍数，取舍就按照0.5倍值界限，大于2.5就升小于就舍。但是如果刚好在中间就不知道了，比如372.5。÷'øF 
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所以请知道的朋友帮忙解答下，我也学学。÷'øF 
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数据修约规则(GB8170-87)中÷'øF 
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   5.1   0.5单位修约÷'øF 
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将拟修约数值乘以2，按指定数位依第3章规则修约，所得数值再除以2。÷'øF 
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          拟修约数值                      乘2                      2A修约值                            A修约值        ÷'øF 
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                 A                               2A                  ( 修约间隔为10）                ( 修约间隔为5）÷'øF 
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              378.3                         756.6                         760                                     380÷'øF 
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              530.7                         1061.4                       1060                                   530÷'øF 
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              372.5                         745                            740                                     370÷'øF 
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二楼的是简化的方法，比较实用，它跟三楼的方法其实是一样的÷'øF 
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不懂？？？？？？？？？？？？？？？？？÷'øF 
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谢谢÷'øF 
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÷'øF 
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二楼的方法很实用÷'øF 
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简单的说就是：1.   ≤2.5尾数为0；÷'øF 
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              2.   2.5～7.5尾数为5；÷'øF 
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              3.   ≥7.5尾数为10，其实尾数也是0.就是10进一位啦！÷'øF 
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简单的说就是：1.  ≤2.5尾数为0；ƒ£ë“<E‹L{www.kiii.cn Õqè‰êù™÷'øF 
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              2.  2.5～7.5尾数为5；ƒ£ë“<E‹L{www.kiii.cn Õqè‰êù™÷'øF 
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              3.  ≥7.5尾数为10，其实尾数也是0.就是10进一位啦！ƒ£ë“<E‹L{www.kiii.cn Õqè‰êù™ ÷'øF 
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÷'øF 
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说的对！！简单明了！÷'øF 
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感谢大家，还是觉得三楼的更具说服力÷'øF 
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