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yzyzz
- 游客
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- 1904
- 2010-01-04
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1#
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发表于 2010-06-21 14:36
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èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø2下列表格中的数据为做CBR试验十所测得的结果，请将所需数据填在表格空白处，并计算CBR2.5和CBR5，P判断该试验是否重做。èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ øèY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø(已知：量力环校正系数C=200N/0.01mm,贯入杆直径d=50mmèY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø荷载测力计百分表读数RèY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
单位压力P(KPa)èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
百分表读数(0.01mmèY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
贯入量LmmèY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø0.9èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
(92)èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
60.5èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
(0.61)èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø1.8èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
(183)èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
106.5èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
(1.07)èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø2.9èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
（èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
151èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø4.0èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
194èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø4.8èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
240.5èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø5.1èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
286èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ øèY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø解：根据贯入杆的单位压力计算公式èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
P=C*R/AèY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø则P=200X0.9/1963=0.092 èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
MPaèY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
0.092X1000=9（KPa）èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ øèY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
P=200X1.8/1963=0.183 MPaèY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
0.183X1000=183 (MPa)èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ øèY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
(其中 A=1/4Πd2èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
=1/4X3.14X502 =1963èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø请问，贯入量是如何计算的？èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø1 某工地地基原状土直剪试验（快剪）结果如下表，试求该地基的强度指标èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
σ (KPa)èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
| 100èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
| 200èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
| 300èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
| τ( KPa)èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
| 100èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
| 108èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
| 115èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
|
èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
解:èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
（1）直剪试验在直角坐标σ~τ关系图是线性的，表达式是τ =σtgΦ+CèY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
(2)作图如下：èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
（3）tgΦ=15%200=0.075èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
Φ=4.3oèY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
C=100-100tgΦèY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
C=92.5(KPa)èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
请问我这样做是正确的吗？那么èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
（3）中的tgΦ=15%200中的15和200是怎样确定的？èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
C=100-100tgΦ中的两个100是怎样确定的？èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
èY¶Û,ú{ÀpQbbs.3c3t.comY8°FÔ¿¿ ø
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