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1#
                                                                                            °Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
2下列表格中的数据为做CBR试验十所测得的结果,请将所需数据填在表格空白处,并计算CBR2.5CBR5P判断该试验是否重做。°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
(已知:量力环校正系数C=200N/0.01mm,贯入杆直径d=50mm°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
荷载测力计百分表读数R°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
单位压力P(KPa)°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
百分表读数(0.01mm°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
贯入量Lmm°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
0.9°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
(92)°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
60.5°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
(0.61)
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
1.8°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
(183)°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
106.5°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
(1.07)
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
2.9°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
151°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
4.0°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
194°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
4.8°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
240.5°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
5.1°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
286°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
解:根据贯入杆的单位压力计算公式°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
P=C*R/A
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
P=200X0.9/1963=0.092 °Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
MPa°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
0.092X1000=9
KPa°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
P=200X1.8/1963=0.183 MPa°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
0.183X1000=183 (MPa)
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
(
其中 A=1/4Πd2°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
=1/4X3.14X502 =1963
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
请问,贯入量是如何计算的?°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
1 某工地地基原状土直剪试验(快剪)结果如下表,试求该地基的强度指标°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
σ (KPa)°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
100°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
200°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
300°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
τ( KPa)°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
100°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
108°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
115°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
:°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
1)直剪试验在直角坐标σ~τ关系图是线性的,表达式是τ =σtgΦ+C°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
(2)
作图如下:°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
3tgΦ=15%200=0.075°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
Φ=4.3
o°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
C=100-100tg
Φ°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
C=92.5(KPa)°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
请问我这样做是正确的吗?那么°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
(3)中的tgΦ=15%200中的15和200是怎样确定的?°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
C=100-100tg
Φ中的两个100是怎样确定的?°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
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