监理检测网论坛

注册

 

返回列表
发新话题 回复该主题
查看: 2212|回复: 0

[交流] 学习交流两习题 [复制链接]

yzyzz
头像

  • 游客
  • 1700
  • 1904
  • 2010-01-04
1#
t T
发表于 2010-06-21 14:36 |只看楼主
                                                                                            °Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
2下列表格中的数据为做CBR试验十所测得的结果，请将所需数据填在表格空白处，并计算CBR2.5和CBR5，P判断该试验是否重做。°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
(已知：量力环校正系数C=200N/0.01mm,贯入杆直径d=50mm°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
荷载测力计百分表读数R°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
单位压力P(KPa)°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
百分表读数(0.01mm°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
贯入量Lmm°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
0.9°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
(92)°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
60.5°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
(0.61)°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
1.8°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
(183)°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
106.5°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
(1.07)°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
2.9°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
（°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
151°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
4.0°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
194°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
4.8°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
240.5°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
5.1°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
286°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
解：根据贯入杆的单位压力计算公式°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
P=C*R/A°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
则P=200X0.9/1963=0.092 °Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
MPa°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
0.092X1000=9（KPa）°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
P=200X1.8/1963=0.183 MPa°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
0.183X1000=183 (MPa)°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
(其中 A=1/4Πd2°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
=1/4X3.14X502 =1963°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
请问，贯入量是如何计算的？°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
1 某工地地基原状土直剪试验（快剪）结果如下表，试求该地基的强度指标°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
σ (KPa)°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
100°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
200°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
300°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
τ( KPa)°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
100°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
108°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
115°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
解:°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
（1）直剪试验在直角坐标σ~τ关系图是线性的，表达式是τ =σtgΦ+C°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
(2)作图如下：°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
（3）tgΦ=15%200=0.075°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
Φ=4.3o°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
C=100-100tgΦ°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
C=92.5(KPa)°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
请问我这样做是正确的吗？那么°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
（3）中的tgΦ=15%200中的15和200是怎样确定的？°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
C=100-100tgΦ中的两个100是怎样确定的？°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
°Ží†àÁ(Úùbbs.3c3t.come¡‰#r½.IÊ
分享 转发
TOP
上一主题| 下一主题
返回列表
发主话题 回复该主题
高级编辑器高级编辑器