如题：某高速公路水泥稳定碎石基层，已知设计抗压强度Rd=3.1MPa,现测得某段的无侧限抗压强度数值如下，对该段强度结果进行评定并计算其得分值。（规定分为20分，保证率为95%，Za=1.645）3.85öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
4.01öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
3.53öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
3.96öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
4.00öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
3.73öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
3.86öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
3.97öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
3.93öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
4.05öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
3.52öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
3.83öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
第一种解答：öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
R=3.85öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
Cv=0.046öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
Rd/(1-ZaCv)=3.1/(1-1.645*0.046)=3.35öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
R>Rd/(1-ZaCv)öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
合格，得满分20分。öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
我看了也有资料上这样解答： öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
答案：öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
（1）计算平均值öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
，标准偏差S、变异系数Cv：R=3.85öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
Cv=0.046 S=0.178öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
（2）计算代表值：öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
保证率为95%的保证率系数Za=1.645öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
∴代表值=3.85-0.178*1.645=3.56öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
（3）评定：öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
∵3.56＞3.2öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
∴该段的无侧限抗压强度合格öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
（4）计算得分值：öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
得分值=20分（规定的满分）öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
个人认为第二种解答求出的是该组数据的代表值，不适用于路段的强度评定，不知大家有何不同见解，欢迎讨论！öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
öànhnÇ·bbs.3c3t.comM$7)Úy \Õ
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