M7.5号砂浆配合比设计 [复制链接]

1,计算试配强度:d@f¦èŠ/¹’bbs.3c3t.comCtl$Ð7ߒ
fm,o=f2+0.645δ=7.5+1.88×0.645=8.7Mpad@f¦èŠ/¹’bbs.3c3t.comCtl$Ð7ߒ
2,确定水泥用量:d@f¦èŠ/¹’bbs.3c3t.comCtl$Ð7ߒ
1000(fm.o-β)d@f¦èŠ/¹’bbs.3c3t.comCtl$Ð7ߒ
1000(8.7+15.09)d@f¦èŠ/¹’bbs.3c3t.comCtl$Ð7ߒ
QC=d@f¦èŠ/¹’bbs.3c3t.comCtl$Ð7ߒ
=d@f¦èŠ/¹’bbs.3c3t.comCtl$Ð7ߒ
=242kg/m3 d@f¦èŠ/¹’bbs.3c3t.comCtl$Ð7ߒ
d@f¦èŠ/¹’bbs.3c3t.comCtl$Ð7ߒ
α*fced@f¦èŠ/¹’bbs.3c3t.comCtl$Ð7ߒ
3.03×32.5d@f¦èŠ/¹’bbs.3c3t.comCtl$Ð7ߒ
d@f¦èŠ/¹’bbs.3c3t.comCtl$Ð7ߒ
3,确定水用量:d@f¦èŠ/¹’bbs.3c3t.comCtl$Ð7ߒ
查表确定用水量为260kg/m3 d@f¦èŠ/¹’bbs.3c3t.comCtl$Ð7ߒ
d@f¦èŠ/¹’bbs.3c3t.comCtl$Ð7ߒ
4,确定砂的用量:d@f¦èŠ/¹’bbs.3c3t.comCtl$Ð7ߒ
用砂在干燥状态下的堆积密度值1480 kg/m3 作为砂的用量.d@f¦èŠ/¹’bbs.3c3t.comCtl$Ð7ߒ
d@f¦èŠ/¹’bbs.3c3t.comCtl$Ð7ߒ
所以基准配合比确定为:水泥:砂:水=295:1480:260 d@f¦èŠ/¹’bbs.3c3t.comCtl$Ð7ߒ
d@f¦èŠ/¹’bbs.3c3t.comCtl$Ð7ߒ
这个295的水泥怎么来的？d@f¦èŠ/¹’bbs.3c3t.comCtl$Ð7ߒ
用水量查表最少都是270呀。d@f¦èŠ/¹’bbs.3c3t.comCtl$Ð7ߒ

既然是配合比设计，那么是否又配合比验证，砂浆的稠度是多少？在确定水泥用量的计算中，qc的用量是242，那基准配比中的295又是从何而来的？d@f¦èŠ/¹’bbs.3c3t.comCtl$Ð7ߒ

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