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[交流] 学习交流两习题 [复制链接]

1#
                                                                                            Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
2下列表格中的数据为做CBR试验十所测得的结果,请将所需数据填在表格空白处,并计算CBR2.5CBR5P判断该试验是否重做。Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
(已知:量力环校正系数C=200N/0.01mm,贯入杆直径d=50mmZ‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
荷载测力计百分表读数RZ‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
单位压力P(KPa)Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
百分表读数(0.01mmZ‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
贯入量LmmZ‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
0.9Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
(92)Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
60.5Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
(0.61)
Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
1.8Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
(183)Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
106.5Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
(1.07)
Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
2.9Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
151Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
4.0Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
194Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
4.8Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
240.5Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
5.1Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
286Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
解:根据贯入杆的单位压力计算公式Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
P=C*R/A
Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
P=200X0.9/1963=0.092 Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
MPaZ‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
0.092X1000=9
KPaZ‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
P=200X1.8/1963=0.183 MPaZ‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
0.183X1000=183 (MPa)
Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
(
其中 A=1/4Πd2Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
=1/4X3.14X502 =1963
Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
请问,贯入量是如何计算的?Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
1 某工地地基原状土直剪试验(快剪)结果如下表,试求该地基的强度指标Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
σ (KPa)Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
100Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
200Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
300Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
τ( KPa)Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
100Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
108Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
115Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
:Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
1)直剪试验在直角坐标σ~τ关系图是线性的,表达式是τ =σtgΦ+CZ‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
(2)
作图如下:Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
3tgΦ=15%200=0.075Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
Φ=4.3
oZ‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
C=100-100tg
ΦZ‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
C=92.5(KPa)Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
请问我这样做是正确的吗?那么Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
(3)中的tgΦ=15%200中的15和200是怎样确定的?Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
C=100-100tg
Φ中的两个100是怎样确定的?Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
Z‰™ŸH=ù k‘bbs.3c3t.com‘•‘êê‡D†ž
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