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1#
                                                                                            i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
2下列表格中的数据为做CBR试验十所测得的结果,请将所需数据填在表格空白处,并计算CBR2.5CBR5P判断该试验是否重做。i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
(已知:量力环校正系数C=200N/0.01mm,贯入杆直径d=50mmi”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
荷载测力计百分表读数Ri”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
单位压力P(KPa)i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
百分表读数(0.01mmi”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
贯入量Lmmi”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
0.9i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
(92)i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
60.5i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
(0.61)
i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
1.8i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
(183)i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
106.5i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
(1.07)
i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
2.9i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
151i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
4.0i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
194i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
4.8i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
240.5i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
5.1i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
286i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
解:根据贯入杆的单位压力计算公式i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
P=C*R/A
i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
P=200X0.9/1963=0.092 i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
MPai”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
0.092X1000=9
KPai”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
P=200X1.8/1963=0.183 MPai”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
0.183X1000=183 (MPa)
i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
(
其中 A=1/4Πd2i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
=1/4X3.14X502 =1963
i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
请问,贯入量是如何计算的?i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
1 某工地地基原状土直剪试验(快剪)结果如下表,试求该地基的强度指标i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
σ (KPa)i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
100i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
200i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
300i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
τ( KPa)i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
100i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
108i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
115i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
:i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
1)直剪试验在直角坐标σ~τ关系图是线性的,表达式是τ =σtgΦ+Ci”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
(2)
作图如下:i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
3tgΦ=15%200=0.075i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
Φ=4.3
oi”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
C=100-100tg
Φi”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
C=92.5(KPa)i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
请问我这样做是正确的吗?那么i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
(3)中的tgΦ=15%200中的15和200是怎样确定的?i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
C=100-100tg
Φ中的两个100是怎样确定的?i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
i”¡“Ég|¨wbbs.3c3t.como4HTdv[×ÙÕ
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